2u^2-5u-25=0

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Solution for 2u^2-5u-25=0 equation:


Simplifying
2u2 + -5u + -25 = 0

Reorder the terms:
-25 + -5u + 2u2 = 0

Solving
-25 + -5u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(-5 + -2u)(5 + -1u) = 0

Subproblem 1

Set the factor '(-5 + -2u)' equal to zero and attempt to solve: Simplifying -5 + -2u = 0 Solving -5 + -2u = 0 Move all terms containing u to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -2u = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -2u = 0 + 5 -2u = 0 + 5 Combine like terms: 0 + 5 = 5 -2u = 5 Divide each side by '-2'. u = -2.5 Simplifying u = -2.5

Subproblem 2

Set the factor '(5 + -1u)' equal to zero and attempt to solve: Simplifying 5 + -1u = 0 Solving 5 + -1u = 0 Move all terms containing u to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1u = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1u = 0 + -5 -1u = 0 + -5 Combine like terms: 0 + -5 = -5 -1u = -5 Divide each side by '-1'. u = 5 Simplifying u = 5

Solution

u = {-2.5, 5}

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